medal and fan awarded what is the exact value of the expression sqrt4y^8 + sqrty^2 - 2sqrty^2 + sqrty^8? simplify is possible 5y^4 + 3y 7y^4 3y^4 + 4y 7y^6
Do you know how to take √ of numbers and √ of exponents?
no.
now consider the first term\[\sqrt{4y ^{8}}\]
Now this can split as \[\sqrt{4} .\sqrt{y ^{8}}\]
ok
now what is √ 4 ?
2
good. Now for taking the sqrt of exponents. Note: You have keep the exponents in even nos. now you have y^8 so leave it like that. if you have y^3 split it as y^2.y Now we have y^8. Taking the √ of exponents is just dividing the exponent by 2, meaning dividing 8/2 and writing y with the new exponent. so \[\sqrt{y ^{8}} = y ^{4}\]
ok
so now you first term reduced to \[2y ^{4}\]
Now can you do the second one. you have √ y² . what will be the sqrt of this?
divide the power by 2 and write the letter with the new exponent.
should not take this much time
gtg can't wait the whole day for you to answer
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