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what is the exact value of the expression sqrt4y^8 + sqrty^2 - 2sqrty^2 + sqrty^8? simplify is possible
5y^4 + 3y
7y^4
3y^4 + 4y
7y^6
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OpenStudy (rajee_sam):
Do you know how to take √ of numbers and √ of exponents?
OpenStudy (anonymous):
no.
OpenStudy (rajee_sam):
now consider the first term\[\sqrt{4y ^{8}}\]
OpenStudy (rajee_sam):
Now this can split as \[\sqrt{4} .\sqrt{y ^{8}}\]
OpenStudy (anonymous):
ok
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OpenStudy (rajee_sam):
now what is √ 4 ?
OpenStudy (anonymous):
2
OpenStudy (rajee_sam):
good. Now for taking the sqrt of exponents.
Note: You have keep the exponents in even nos.
now you have y^8 so leave it like that. if you have y^3 split it as y^2.y
Now we have y^8. Taking the √ of exponents is just dividing the exponent by 2, meaning dividing 8/2 and writing y with the new exponent.
so \[\sqrt{y ^{8}} = y ^{4}\]
OpenStudy (anonymous):
ok
OpenStudy (rajee_sam):
so now you first term reduced to \[2y ^{4}\]
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OpenStudy (rajee_sam):
Now can you do the second one. you have √ y² . what will be the sqrt of this?
OpenStudy (rajee_sam):
divide the power by 2 and write the letter with the new exponent.