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Mathematics 16 Online
OpenStudy (anonymous):

Evaluate the double integral (2int4)(1int9)ye^x dydx

OpenStudy (amistre64):

hold e^x constant: k what is the integration of ky dy?

OpenStudy (anonymous):

Isn't it ky^2/2?

OpenStudy (amistre64):

yes soo k9^2/2 - k1^2/2 k(81/2 - 1/2) 40k now integrate 40 e^x dx

OpenStudy (anonymous):

40e^x + c

OpenStudy (amistre64):

the +C is not needed when we have limits

OpenStudy (anonymous):

So it's 40e^4-40e^2?

OpenStudy (amistre64):

40e^4 - 40e^2 yes

OpenStudy (anonymous):

Fanned. You are so smart!

OpenStudy (amistre64):

i have my moments of clarity :) good luck

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