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Mathematics
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Evaluate the double integral (2int4)(1int9)ye^x dydx
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hold e^x constant: k what is the integration of ky dy?
Isn't it ky^2/2?
yes soo k9^2/2 - k1^2/2 k(81/2 - 1/2) 40k now integrate 40 e^x dx
40e^x + c
the +C is not needed when we have limits
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So it's 40e^4-40e^2?
40e^4 - 40e^2 yes
Fanned. You are so smart!
i have my moments of clarity :) good luck
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