Question

Derivative of y=ln(sinx)

Answer 1

do u understand?

Answer 2

Um you multiply it by the derivative ?

Answer 3

I thought, ln(x) = 1/x

Answer 4

:S

Answer 5

Thanks !!

Answer 6

I'm aware of the chain rule

Answer 7

http://math2.org/math/derivatives/more/ln.htm

Answer 8

do u wanna watch a 5 min video about chain rule proof

Answer 9

http://www.youtube.com/watch?v=7HpqWjOcrUc

Answer 10

Thanks :)

Answer 11

Can you help me with one more thing please ?

Answer 12

ya sure

Answer 13

dont watch that video, the proof seems longer than expected.. ill find another one

Answer 14

It's okay, I already have the proof written in my note book :)

Answer 15

hmm

Answer 16

\[\large f(x)= \log_{4} (3x+1)^b\]

Answer 17

do u really??

Answer 18

\[\large f'(x) = \frac{ 1 }{ (3x+1)^bln(4) }\]

Answer 19

Would that be right or not ?

Answer 20

where is this ln(4) coming from

Answer 21

Well my teacher gave us a note today, " If \[\large y=\log_{b} x\] then

Answer 22

\[\frac{ dy }{ dx } = \frac{ 1 }{ xlnb }\]

Answer 23

ok. well in this case is x is a X(x) right

Answer 24

so u gotta multiply by that derivative

Answer 25

" x is a X(x) " < I dont understand what you mean by that

Answer 26

you got y=Log(b)f(x) not just x

Answer 27

But it just says 'x' :S

Answer 28

and the
f'(x)=dy/dy ( 3x+1)^b = b(3x+1)^b-1 * 3

Answer 29

i mean that x there isnt just x* its a function of X

Answer 30

so u gotta multiply by f'(x)