Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

help!!!!!!!!!!!!!!!!!!!!!

OpenStudy (anonymous):

use unit circle and 30 60 90 triangles to find the values in degrees of each expression cos^-1 (sqrt3)/2

OpenStudy (anonymous):

@chrisplusian help me please

OpenStudy (anonymous):

do you have a copy of the triangle?

OpenStudy (anonymous):

no i dont

OpenStudy (anonymous):

then you need one !

OpenStudy (anonymous):

how do i get it

OpenStudy (anonymous):

do you mean the sheet you gave me

OpenStudy (anonymous):

i have that

OpenStudy (anonymous):

http://www.freemathhelp.com/triangle-30-60-90.html

OpenStudy (chrisplusian):

I would set \[y=\cos^{-1}(\frac{ \sqrt{3} }{ 2 })\] if you take the cosine of both sides you get \[\cos(y)=\frac{ \sqrt{3} }{ 2 }\] cos is the x value in the unit circle.so the cosine value =\[\frac{ \sqrt{3} }{ 2 }\] at \[\frac{ \pi }{ 6 }\] or 30 degrees

OpenStudy (anonymous):

thank you!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!