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Algebra 15 Online
OpenStudy (anonymous):

|2y-2|=y

OpenStudy (anonymous):

Is that staeted correctly, there's no x value?

OpenStudy (anonymous):

stated*

OpenStudy (anonymous):

yeah. @viper_feronzie

OpenStudy (jkristia):

maybe you have to solve for y instead of x. You know what absolute value means ? e.g. a super simple example, if you had to solve for | -5 | = x then you know that |5 | = x is also an answer, so you could solve it as (5) = x and -(5) = x or as 5 = x and 5 = -x Same will work in your equation, there will be 2 y values which satisfy the equation

OpenStudy (anonymous):

ok thanks

OpenStudy (jkristia):

do you know how to solve it now ?

OpenStudy (anonymous):

would it be {2, 3}

OpenStudy (anonymous):

@jkristia

OpenStudy (jkristia):

if you try 2 then you get |2(2) - 2 | = 2 ? |4 - 2 | = 2, yes, so 2 is ok, try the same with 3 |2(3) - 2| = 3 ? |6 - 2| = 3, no - so 3 is not a correct value so you solved 2y - 2 = y => y = 2 now try solve the other case 2y - 2 = -y

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