Question

evaluate (2x^2-5y)/(3x-y) when x=2 and y =-4

Answer 1

\[\Large \frac{2\color{red}x^2-5\color{blue}y}{3\color{red}x-\color{blue}y}\]

Answer 2

PLato?

Answer 3

as @terenzreignz has pointed out...simply plug in (2) for every 'x' that you see...and plug in (-4) for every 'y' that you see

Answer 4

lol I haven't actually pointed anything out, I just rewrote the expression
:3

Answer 5

@terenzreignz idk I think that highlighting of the 'x' and 'y' really brings the point home :D

Answer 6

Let's be formal, then :D
\[\Large \color{red}x = \color{red}{2}\]\[\Large \color{blue}{y}=\color{blue}{-4}\]