Question

I did this problem and i somehow got x=-36. help please?
(Problem in comments)

Answer 1

Solve for x in the proportion .

x = 3 and x = −4

x = −3 and x = 4

x = −3

x = −12

Answer 2

cross multiply

3x^2 = -3x + 36

Answer 3

$$
\cfrac{3x}{3x-36}=\cfrac{-1}{x} \implies \cfrac{3x}{3(x-12)}=\cfrac{-1}{x}\\
\implies \cfrac{x}{x-12}=\cfrac{-1}{x}\\
\color{blue}{x(x-12)} \times \cfrac{x}{x-12}=\cfrac{-1}{x} \times \color{blue}{x(x-12)}\\
$$
what would that give you?

Answer 4

3x^2+3x-36= 0 now factor it

3(x^2+x-12 )=0
3(x+4)(x-3)= 0

x+4 = 0 or x-3=0 now solve for x

Answer 5

@Jim766 so x=-4 and x=3?

Answer 6

right !

Answer 7

oh! okay! thanks!(:

Answer 8

yw