Question

The equation 7cos((pi/3)t) models the height h in centimeters after t seconds of a weight attached to the end of a spring that has been stretched and then released.

Answer 1

a. solve the equation for t.
\[h=7\cos \left(\begin{matrix}\pi \\ 3\end{matrix}\right)t\]

Answer 2

\[h \left(\begin{matrix}3 \\ \pi\end{matrix}\right) = 7\cos t\]

Answer 3

is this right so far? @jim_thompson5910

Answer 4

\[\large h = 7\cos\left(\frac{\pi}{3}t\right)\]


\[\large \frac{h}{7} = \cos\left(\frac{\pi}{3}t\right)\]


\[\large \cos\left(\frac{\pi}{3}t\right) = \frac{h}{7}\]


\[\large \frac{\pi}{3}t = \pm\arccos\left(\frac{h}{7}\right)\]


\[\large t = \pm\frac{3}{\pi}\arccos\left(\frac{h}{7}\right)\]

Answer 5

that's what you should get when you solve for t