Question

part a. write an equation of the line that is paralell to the link y = 5x - 4 and contains the point (-3, 6).
part b. Write the equation of a line that is perpendicular to the line y = 1/2x and contains the point (2,5)

Answer 1

to write and equation of a line you need a slope and a y intercept

parallel lines have the same slope,
so if your line is parallel to y = 5x -4 , then your slope must also be 5

Answer 2

Do i need to do any type of formulas so solve?

Answer 3

if your slope is 5, now all you need is y intercept

y = mx + b , the b is the y intercept , substitute in the (-3, 6)
and the slope and then solve for b

6 = 5(-3) + b

Answer 4

how do you get the b alone?

Answer 5

what is 5(-3) =

Answer 6

Would it be -15

Answer 7

right
6 = -15 + b , now how do you get rid of the -15?

Answer 8

would you add the -15 to the 6, then what you have left is -9b..?

Answer 9

6 = -15 + b
+15 +15
21 = b

Answer 10

where did the -9b come from?

Answer 11

I added 6 to each side... lol

Answer 12

lol ...anyway if your b = 21 and m = 5 all you have to do is
put them both into y = mx + b
y = 5x + 21

Answer 13

you ready to try b?

Answer 14

yes sir

Answer 15

lol..

Answer 16

this is the same , but different lol

Answer 17

perpendicular lines do not have the same slopes....
they are opposites (different signs) and reciprocals (flip the fraction

if their slope is 1/2 the perpendicular slope will be opposite and reciprocal

that one is positive, so mine is negative.... do you know what is the reciprocal of 1/2