Question

help @jdoe0001 @Jim766

Answer 1

o i forgot @jim_thompson5910

Answer 2

same thing as jim_thompson5910 already showed you, same equation he used, just make the "a" negative :)

Answer 3

ok

Answer 4

let's see, for a parabola whose vertex is (2, -4)
$$
(\color{red}{h},\color{blue}{k}) \implies (\color{red}{x},\color{blue}{y}) \implies
(\color{red}{2},\color{blue}{-4})\\
\text{a point value given is } (-3,-3)\\
-3=-a(-3-\color{blue}{(-4)})^2+\color{red}{(2)}\\
$$
from there just solve for "a", positive "a" that is :)

Answer 5

i thought it was supposed to be a negative a?

Answer 6

it's, the horizontal parabola is opening leftward

Answer 7

for the equation is a negative "a", or "-a", but you want to find "a", then slap it with a minus :)

Answer 8

so it changes to a -3=-a(-3+4))=2?

Answer 9

well, what would be in say \(-a(-3+4)^2\)?

Answer 10

yea

Answer 11

so, what would that part give you?

Answer 12

-a(1)^2

Answer 13

right, so that part becomes -a, because \(1^2 =1\) and -a*1 =-a, so the equation becomes

-3 = -a +2

solving for "a" what would that give?

Answer 14

-1?

Answer 15

-1?

Answer 16

idk;(

Answer 17

ok, lemme put it this way

3 = a - 2

what would "a" give you?

Answer 18

add 3 to both sides?

Answer 19

we're under the assumption you know how to factor :S

Answer 20

caz that gave me 1

Answer 21

well, if you add 3 to both sides, you'd get

6 = a + 5

Answer 22

not

Answer 23

6 = a +1

Answer 24

ughhh

Answer 25

woops, I need to dash

Answer 26

whats the answer can you tell me

Answer 27

@GuardianOfLore