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Mathematics 19 Online
OpenStudy (unicornpoopcookies):

Help!! Will give Medals!

OpenStudy (unicornpoopcookies):

OpenStudy (luigi0210):

This is arc length if I'm not mistaken?

OpenStudy (luigi0210):

Use this: \[\frac{ n }{ 360 }*2\Pi r\]

OpenStudy (luigi0210):

n=degrees r=radius

OpenStudy (anonymous):

We are looking for the area of the shaded region, which is a third of the circle. The area of a circle is \[pir ^{2}\] So just divide that area by 3 to find the area of the shaded region.

OpenStudy (anonymous):

luigi's answer explains it better, but you end up with the same thing.

OpenStudy (luigi0210):

Oops, nevermind sorry

OpenStudy (anonymous):

Oh, except it's pir^2 instead haha.

OpenStudy (anonymous):

instead of 2pir :p

OpenStudy (unicornpoopcookies):

120/360 x 2 pi 8?

OpenStudy (anonymous):

120/360 * pir^2

OpenStudy (luigi0210):

well actually the formula I looked up had 2pir

OpenStudy (anonymous):

That is the formula for circumference of a circle. This question is asking for area of the shaded region.

OpenStudy (anonymous):

That would solve the line XY if you used 120/360 * 2pir

OpenStudy (luigi0210):

Oops, yea sorry about that

OpenStudy (unicornpoopcookies):

= 67.05? @Luigi0210

OpenStudy (luigi0210):

well actually 134.04

OpenStudy (unicornpoopcookies):

It was 66.99 - 67.02

OpenStudy (anonymous):

120/360 * pi(64) = 67.02

OpenStudy (luigi0210):

wait, it;s 2pi-134.04

OpenStudy (anonymous):

r = 8 pi (r^2) 64pi

OpenStudy (luigi0210):

dang it.. sorry about that

OpenStudy (luigi0210):

Err, geometry was never my favorite..

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