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OpenStudy (unicornpoopcookies):
OpenStudy (luigi0210):
This is arc length if I'm not mistaken?
OpenStudy (luigi0210):
Use this:
\[\frac{ n }{ 360 }*2\Pi r\]
OpenStudy (luigi0210):
n=degrees
r=radius
OpenStudy (anonymous):
We are looking for the area of the shaded region, which is a third of the circle.
The area of a circle is
\[pir ^{2}\]
So just divide that area by 3 to find the area of the shaded region.
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OpenStudy (anonymous):
luigi's answer explains it better, but you end up with the same thing.
OpenStudy (luigi0210):
Oops, nevermind sorry
OpenStudy (anonymous):
Oh, except it's pir^2 instead haha.
OpenStudy (anonymous):
instead of 2pir :p
OpenStudy (unicornpoopcookies):
120/360 x 2 pi 8?
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OpenStudy (anonymous):
120/360 * pir^2
OpenStudy (luigi0210):
well actually the formula I looked up had 2pir
OpenStudy (anonymous):
That is the formula for circumference of a circle. This question is asking for area of the shaded region.
OpenStudy (anonymous):
That would solve the line XY if you used 120/360 * 2pir
OpenStudy (luigi0210):
Oops, yea sorry about that
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OpenStudy (unicornpoopcookies):
= 67.05? @Luigi0210
OpenStudy (luigi0210):
well actually 134.04
OpenStudy (unicornpoopcookies):
It was 66.99 - 67.02
OpenStudy (anonymous):
120/360 * pi(64) = 67.02
OpenStudy (luigi0210):
wait, it;s 2pi-134.04
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