Question

Solve the following equation by transforming it into a perfect square trinomial:
x^2 – 2x = 3

Answer 1

x² - 2x = 3
x² - x = 3 + (- 1)²
x² - x = 3 + 1
(x - 1)² = 4
x - 1 = 4

x = 4 + 1, x = 5
x = - 4 + 1, x = - 3

Answer: (- 3, 5)

Answer 2

thanks again :)

Answer 3

Anytime.

Answer 4

even though you have to solve it using a square BInomial, you can solve it using the quadratic formula too. \[y=ax^2+bx+c\] formula to follow
\[x^2-2x-3=0\]\[(x-3)(x+1)=0\]solve for x \[(x-3)=0\]\[(x-2)=0\]\[x=3,2\]

Answer 5

@Nurali "x-1=4" JUST equals x=5.

With \[\sqrt{(x-1)^2} = |x-1| , |x-1| \neq x-1\]