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Algebra 12 Online
OpenStudy (anonymous):

How do you solve x4+200=102x2?

OpenStudy (anonymous):

Factoring will get you there. This is a modified case of something you probably know well.

OpenStudy (anonymous):

Should i move the 102x2 to the left?

OpenStudy (anonymous):

Good start.

OpenStudy (anonymous):

then factor out the X2 right? then what i always get stuck here

OpenStudy (anonymous):

Now you have \[x^{4} - 102x ^{2}+ 200 = 0\]. What if it was squared and first power instead of powers 4 and 2? Could you factor?

OpenStudy (anonymous):

Okay so factor out the X2 then it would be x2(x2-102)+200

OpenStudy (anonymous):

That is right in a way, but you should do the type of factoring that gives you a pair of parentheses instead of just getting a greatest common factor.

OpenStudy (anonymous):

okay... so what method would be the best?

OpenStudy (anonymous):

(x2 )(x2 ) would be how it would look roughly. You then have to determine what would make each parentheses = 0

OpenStudy (anonymous):

okay thanks

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