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Mathematics 9 Online
OpenStudy (anonymous):

Hey guys ;) Im having a really hard time with this question. Could ANYONE possibly help?? What is the length, in units, of JK? (Picture below)

OpenStudy (anonymous):

OpenStudy (raden):

use this formula : JK^2 = JM * JL so, JK^2 = 8 * 16 solve for JK (then simplify it)

OpenStudy (anonymous):

This is a right triangle, so Pythagoras could help. Label EVERYTHING you can. What do you notice about the two smaller triangles?

OpenStudy (amistre64):

.... golden ratio comes to mind as well :) but my mind is not what it used to be ...

OpenStudy (raden):

yeah, i used the similarity of triangles JKM and JKL :) JK/JL = JM/JK, therefore JK^2 = JM * JL

OpenStudy (anonymous):

RadEn, I saw your excellent idea. I was trying to nudge the student to consider you solution for future use.

OpenStudy (anonymous):

I like RadEn answer the best, it was very helpful. Thank you

OpenStudy (raden):

welcome :)

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