Question

How do i solve log(x^2+7)=3 plz show ur work

Answer 1

apply the exponential function on both sides, you obtain \(x^2+7=e^3\). you can solve this formula easily. (two solutions)

Answer 2

umm, in lower math classes, log is base 10, not natural

Answer 3

so this is either =10^3, or =e^3 :/

Answer 4

oh ok. then what you do is
\[10^{\log_{10}(x^2+7)} = 10^3\\
x^2+7 = 10^3\]. thanks for the reminder

Answer 5

real analysis gets into the "log" function as the natural log :)

Answer 6

i am lost

Answer 7

we are wondering if your log is actually \(\log_{10}\) or \(\log_e\) . but the method is the same.

Answer 8

i dont know my teacher gave me this got extrca cridet

Answer 9

if you don't kow, just say that you choose \(\log_{10}\), and do as in my msg starting with "oh ok". gl.

Answer 10

ok tysvm