How do i solve log(x^2+7)=3 plz show ur work

Question

reemii · Answer

apply the exponential function on both sides, you obtain $x^2+7=e^3$. you can solve this formula easily. (two solutions)

amistre64 · Answer

umm, in lower math classes, log is base 10, not natural

amistre64 · Answer

so this is either =10^3,  or =e^3  :/

reemii · Answer

oh ok. then what you do is
$$10^{\log_{10}(x^2+7)} = 10^3\
x^2+7 = 10^3$$. thanks for the reminder

amistre64 · Answer

real analysis gets into the "log" function as the natural log  :)

anonymous · Answer

i am lost

reemii · Answer

we are wondering if your log is actually $\log_{10}$ or $\log_e$ . but the method is the same.

anonymous · Answer

i dont know my teacher gave me this got extrca cridet

reemii · Answer

if you don't kow, just say that you choose $\log_{10}$, and do as in my msg starting with "oh ok". gl.

anonymous · Answer

ok tysvm