Can someone check my answer?
In a bike race, a rider covers a 5 mi flat stretch of road at a speed of s mi/h. She then doubles her speed down a hill 1 mi long. Finally, she reduces her downhill speed bu 12 mi/h as she rides the last 3 mi of the race. What function gives the time t it takes the rider finish the race in terms of s?
total time = 5/s + 1/2s + 3/(2s-12) IS CORRECT wondering how you got 4s-11
Thank you so much and i got really confused, i thought the answer was what you put but my cousin was also helping me and got that.
on simplification, i get (7s-33)/s(s-6)
So (7s-33) / s(s-6) is the correct simplified answer?
yes.
ok so where (4s-11) / s(s-6) is is where (7s-33) / s(s-6) goes?
lol yes! why don't you try to work out and get 7s-33 yourself and be sure about it :)
Ok i will, thanks again :)
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