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Mathematics 24 Online
OpenStudy (anonymous):

imagine you are the owner of a pizza shop that offers three different types of crust, seven different toppings, and three different cheeses. How many different combinations of 1 crust, 3 topping, 1 cheese pizza does your shop offer?

OpenStudy (anonymous):

Are you familiar with permutations and combinations?

OpenStudy (anonymous):

Yes I am. That is the topic we are studying right now in math, but I've an answer in two times but my teacher said they were incorrect.

OpenStudy (anonymous):

What have you said so far?

OpenStudy (anonymous):

Well the first answer I sent in was 252, but I confused myself and put in the wrong equation. The second answer was 1260. I used the formula he gave in the example problem but I can't seem to get it.

OpenStudy (anonymous):

Using the fundamental counting principle we have 3 choices to multiply together. # of possible crusts X # of combinations of 3 ingredients X # of possible cheeses Does that match you analysis so far?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Since the order the toppings are placed doesn't matter, we use combination \[C_{3}^{7}\] so... 3 X combinations X 3

OpenStudy (anonymous):

Would it be 3 X 35 X 3?

OpenStudy (anonymous):

That is what I got.

OpenStudy (anonymous):

So then there would be 315 different combinations

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