find the polynomial f(x) that has the roots of -3 and 1 multiplicity of 2

Question

campbell_st · Answer

well 

$$P(x) = a(x + 3)(x -1)^2 $$

a is just a constant...

anonymous · Answer

im really bad at this....i dont get it at all

campbell_st · Answer

ok... 

if x + 3 is a factor of a polynomial then x - 3 is a zero

and multiplicity tells you how many times the factor  occurs...

so based on the information provided

the factors of the polynomial are 

(x + 3) and (x -1) and (x -1)     ( multiplicity of 2)

so the polynomial can be written as the product of the factors... 

$$P(x) = (x + 3)(x -1)^2$$

you may need to distribute to get the expanded equation. 

Hope this helps.

anonymous · Answer

thank you!!!

anonymous · Answer

can someone help me with this example!!