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Mathematics 20 Online
OpenStudy (anonymous):

What is the center of the circle given by the equation (x + 5)2 + (y - 8)2 = 1?

OpenStudy (anonymous):

Do you know the standard formula for a circle? HINT: What do h and k have to do with it?

OpenStudy (anonymous):

2x+10+2y-16=1 Thats all i got

OpenStudy (anonymous):

A. (-5, -8) B. (5, -8) C. (5, 8) D. (-5, 8)

OpenStudy (anonymous):

Those 2s are exponents you don't have to use. \[(x-h)^{2} + (y-k)^{2} = r ^{2}\] is the standard form. the h and k are the coordinates of the center (h,k), however; because of the way this formula is written you have to think of h and k as what would make their parentheses = 0.

OpenStudy (anonymous):

D

OpenStudy (anonymous):

Correct

OpenStudy (anonymous):

nice.. thanks guys(:

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