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Mathematics
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Inverse of a function
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@Luigi0210 @Jhannybean
What have you tried?
Well, I know you are supposed to switch the variables.
\[x=\frac{ 3y-1 }{ 2 }\] \[2x=3y-1\] \[y=\frac{ 2x }{ 3 }+\frac{ 1 }{ 3 }\] Now plug in 3 and solve!
7/3 Is that right?
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Good. Now do what luigi said and see if you get what ivan said. I would suggest working it all out for yourself since they might not be around when a new problem comes along.
Sure, Give me a sec
6/3+1/3=7/3
There you go
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