Question

help please!!!!

Answer 1

Two mechanics worked on a car. The first mechanic worked for 10 hours, and the second mechanic worked for 5 hours. Together they charged a total of 1425 . What was the rate charged per hour by each mechanic if the sum of the two rates was 170 per hour?

Answer 2

give me a sec I need more brain juice

Answer 3

okayy

Answer 4

lol you have 2 equations

10x + 5y = 1425
x + y = 170

Do you know how to solve a system of equations?

Answer 5

@Mpinkham What is @johnweldon1993 is doing is exactly what is required to solve this problem.

Answer 6

i subtracted the equations and got 9x+4y=1255

Answer 7

Not quite how to solve it

There could be 2 ways to solve this....the elimination method...or the substitution method....I will be using the substitution method here alright?

Answer 8

okayy

Answer 9

It states that when you have 2 equations....you solve 1 equation for some variable

meaning here....lets solve that 2nd equation for 'y'

x + y = 170

how would we solve that equation for 'y'?

Answer 10

Iould do with another lesson in this stuff cuz I forgot

Answer 11

y=-x+170

Answer 12

great! so now...we know what Y equals...we can now SUBSTITUTE that in for 'y' in the first equation

10x + 5y = 1425

replace 'y' with what we know 'y' equals

10x + 5(-x + 170) = 1425

what would we do next?

Answer 13

10x-5y+850=1425

Answer 14

meant x

Answer 15

remember......nvm you caught it :)

okay so we have

10x - 5x + 850 = 1425

What next?

Answer 16

5x+850= 1425 then 5x=575

Answer 17

GREAT....and then x = ?

Answer 18

115

Answer 19

perfect....we now know what x equals....and we can put that into our second "original" equation to solve for 'y'

x + y = 170
115 + y = 170

what is 'y'?

Answer 20

55?

Answer 21

great.....so we have that mechanic 1 charges 115 an hour....and mechanic 2 charges 55 an hour.....and we can finally check it...by plugging those into that first original equation

10x + 5y = 1425

10(115) + 5(55) = 1425

is that a correct statement?

Answer 22

yeah!!! THANKS!!!!!!!!

Answer 23

if i need more help ill ask

Answer 24

anytime :)

Answer 25

can u help again??? with the settting it up

Answer 26

of course :)