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A bin contains 3 red balls, 4 green balls, and 1 blue ball. Two balls are randomly chosen from the bin. How many color combinations are possible?
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12 i think
@micheal_algebra2 can you please explain how you arrived at that??
these are the answer choices . . 5 3 8 7
multiplied all options together 3*4*1=12
But you can't forget about the 2 balls that are randomley chosen . . right ?
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you can gave two reds, two green, a red and green, a red and blue, or green and blue so its 5 sorry
Thank you .
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