Which of the following equations represents the graph of a line that is perpendicular to the graph of y = kx + b (where k and b are constants) and goes through the point (3, -4)?
A) y + 4 = k(x - 3)
B) y - 4 = k(x + 3)
C) y + 4 = (-1/k)(x - 3)
D) y - 4 = (-1/k)(x + 3)

Question

Which of the following equations represents the graph of a line that is perpendicular to the graph of  y = kx + b (where k and b are constants) and goes through the point (3, -4)?
A) y + 4 = k(x - 3)
B) y - 4 = k(x + 3)
C) y + 4 = (-1/k)(x - 3)
D) y - 4 = (-1/k)(x + 3)

anonymous · Answer

1. Find the slope of the perpendicular, using slope1*slope2 = -1
2. Find the intercept using the given points

anonymous · Answer

Use the imformation given:
Point (3,-4) =$$(x_{1},y_{1})$$
In order to be perpendicular it slope must be the reciprocal negative of the other line 
that is m = -1/k
Use the slope point formula :
$$y-y_{1}=m(x-x_{1})$$
plug in the information given in the formula
$$y +4 = \frac{ -1 }{ k}\left( x-3)\right)$$