Which of the following equations represents the graph of a line that is perpendicular to the graph of y = kx + b (where k and b are constants) and goes through the point (3, -4)?
A) y + 4 = k(x - 3)
B) y - 4 = k(x + 3)
C) y + 4 = (-1/k)(x - 3)
D) y - 4 = (-1/k)(x + 3)

Question

Which of the following equations represents the graph of a line that is perpendicular to the graph of y = kx + b (where k and b are constants) and goes through the point (3, -4)?
A) y + 4 = k(x - 3)
B) y - 4 = k(x + 3)
C) y + 4 = (-1/k)(x - 3)
D) y - 4 = (-1/k)(x + 3)

anonymous · Answer

C,D
the product of slopes of two perpendicular line is (-1).

anonymous · Answer

C
the product of the slopes of two perpendicular lines is -1
and since it passes through (3,-4),
(y-(-4))=(-1/k)(x-3)
y+4=(-1/k)(x-3)