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Based on the lesson, which of the following would be the best approach for solving this system by substitution? 5x = y + 6 2x - 3y = 4 Solve the first equation for x. Solve the first equation for y. Solve the second equation for x. Solve the second equation for y.
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erm....make both equations equal to zero by moving 5x and 4 across... then equate both and move like terms to one side
second option seems best to me, no division required
I would solve the second one for y, and just plug in.
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