Question

plse help me to solve these equations

Answer 1

in both side, multiply LCM.

Answer 2

ex) 1/2 + 1/3 + 1/5
LCM is 2x3x5

Answer 3

30
but no use
it can't be solved

Answer 4

umm.. 1st question's LCM is 60xy.

Answer 5

i think we can't solve it

Answer 6

you can try to add number and remove it to make a square + a number so it can be solve

Answer 7

do u get what i mean ?

Answer 8

if we multiply 1st by 60xy
we have
\[60y-60x=xy\]
second one
\[60(2-y+x+2)=(x+2)(y-2)\]

Answer 9

\[240-60y+60x=xy-2x+2y+4\]
\[244-62y+62x=xy\]

Answer 10

\[244-62y+62x=60y-60x\]
\[244=122y-122x\]
hence
\[60y-60\dfrac{122y-244}{122}=y\dfrac{122y-244}{122}\]

Answer 11

\[122y^2-244y-60*122y+60*122y-244*60=0\]
basic quadratic equation

Answer 12

another method
\[\frac{1}{x+2}=\frac{1}{y-2}-\frac{1}{60}=\frac{62-y}{60y-120}\]
so
\[\frac{1}{x}=\frac{6y-120-2(62-y)}{62-y}\]
so we can reaplace this in equation 1
\[\frac{1}{y}+\frac{6y-120-2(62-y)}{62-y}=\frac{1}{60}\]
\[62*60-60y+y(20)(8y-244)=60y(62-y)\]
basic equation

Answer 13

but i m not geting answer

Answer 14

are they all one big problem?