Question

what is the equation, in standard form, of a parabola that models the values in the table?

Answer 1

General parabolic form
y = (x+b/2) -(b/2)^2 + c
Thus the parabola is shifted horizontally by -b/2 and vertically by -(b/2)^2=c
In your case
y = (x + B)^+C
1 : -6=B^2 +C
2 : 4 = (-2+B)^2+C
3: 70=(4+B)^2+C
subtract one equation from the other to eliminate C, solve for B, then place B in other equation to solve for C

Answer 2

thank you guys :)