Question

If y varies inversely as x, and y = 18 when x = 2, find y when x = 4.

Solve, using the quadratic formula: 2x2 - 3x + 1 = 0

Factor: 36x2 - 25

Answer 1

#2 :

3 +/- sqrt(9 - (4(2)(-1)) / 2(2)

3 +/- sqrt(9 +8) / 4

3 +/- sqrt(17) / 4

[3 + sqrt(17)] / 4
and
[3 - sqrt(17)] / 4


# 3

(6x - 5) (6x + 5) I Think

Answer 2

#2 ... Doesn't have those answers?? @Reppinthe80

Answer 3

o.o Really ?

Answer 4

Yes...

Answer 5

{1, 0.5}


{2.4, -0.9}


{-1, -0.5}


{-2.4, 0.9}
here are the answers @Reppinthe80

Answer 6

These are 3 different questions?

Answer 7

yes @DoYourHomework

Answer 8

-_____- this Makes No Sense !!! O:

Answer 9

That is why I need help lol... It's hard!! @Reppinthe80

Answer 10

Ok...for the first one.
When x is multiplied by 2, y is divided by 2 because it is inversely proportional
so.

x=2*2 = 4
So
y=18/2 = 9

\[x = 4\]
y = 9

see?

Answer 11

Yessss.!! :)

Answer 12

The second one you just have to factor

This is the answer. Try to figure out how I got it.

\[(x-1)(2x-1)\]
x = 1
and
x = 1/2

The third one is the same thing You just have to think a little bit.

"What is the square root of 36 and 25?"

\[(6x-5)(6x+5)\]

Notice that when we FOIL this out.

\[(6x*6x) + (6x*5 +6x*(-5)) -25\]

(6x*5 +6x*(-5)) = 0

So you're back with your original

\[36x^2 - 25\]

Answer 13

Does this make sense? I hope I made it clear.