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Geometry 11 Online
OpenStudy (nerdy_3000):

Can someone check these and help me with both? http://oi39.tinypic.com/2qish7r.jpg

OpenStudy (anonymous):

So for 107 we have that <A=26 <B=64 <C=90

OpenStudy (anonymous):

And BC=2 AC=4.1 AB=4.5

OpenStudy (nerdy_3000):

So the 90 is coming from the angle measure of the triangle,right?

OpenStudy (anonymous):

Well it says it's a right triangle which means it's 90 degrees.

OpenStudy (nerdy_3000):

okay!

OpenStudy (anonymous):

Also, For the sides. \[\cos 26 =\frac{ x }{ 4.5 }\] \[4.5\times \cos 26=x\] \[2.91113695048=x\] or \[2.9=x\] AC=2.9

OpenStudy (anonymous):

Then for the other side \[\cos64=\frac{ y }{ 4.5 }\] \[4.5\times \cos 64=y\] \[1.76335753693=\] or \[1.8=y\] BC=1.8

OpenStudy (nerdy_3000):

For the next one. I know I do this but what do I need to plug in or do I have to plug something in? \[\sin^{-1} \frac{ 4 }{ 126 }\]

OpenStudy (nerdy_3000):

^108.

OpenStudy (anonymous):

Well first off where did you get 126?

OpenStudy (anonymous):

Do this. \[\cos^{-1} (\frac{ 4 }{ 13.6 })\] To find angle B.

OpenStudy (nerdy_3000):

Is there a calculator online to do this???

OpenStudy (anonymous):

Go to google and search 4/13.6 a calculator will pop up.

OpenStudy (nerdy_3000):

Then what should I do with the Cos^-1

OpenStudy (anonymous):

Do \[\cos^{-1}(0.29411764705)\] But that comes out as 1.27226412562 which seems a little odd...

OpenStudy (anonymous):

@phi @amistre64

OpenStudy (anonymous):

@kausarsalley

OpenStudy (nerdy_3000):

@RoseDryer I found this calculator and it gave me this answer

OpenStudy (anonymous):

what are you trying to find??

OpenStudy (nerdy_3000):

108 so far

OpenStudy (anonymous):

are you finding the length of AB on question 107??

OpenStudy (anonymous):

are you there??

OpenStudy (nerdy_3000):

no 108...sorry

OpenStudy (anonymous):

so are you finding the length AB??

OpenStudy (nerdy_3000):

Well the a and b are separated but yes

OpenStudy (anonymous):

what you found for b is right.

OpenStudy (nerdy_3000):

okay! then what should I do for the lowercase ones??

OpenStudy (anonymous):

don't you think the lower case ones are suppose to be for the lengths and the upper case onea are for angles you are supposed to find??

OpenStudy (nerdy_3000):

Yes, so the lowercase ones is 72.9 or is it the m<B

OpenStudy (anonymous):

i am saying that isn't is supposed to look like this?: a=4 b=13 c=13.6 and what you are left to find is m<A, m<B and m<C??

OpenStudy (anonymous):

just asking you to be sure if it is nit like that, then okay..

OpenStudy (nerdy_3000):

Well see this is what I have so far.

OpenStudy (anonymous):

the distances you find are for the lower case letters and the angles you find are for the upper case letters

OpenStudy (nerdy_3000):

Alright so the ones I have are correct?

OpenStudy (anonymous):

if that is the case, then a=4 b=13.0 c=13.6

OpenStudy (nerdy_3000):

Thank You Very Much!!!!! :-)

OpenStudy (anonymous):

is that it?? are you not supposed to find m<A, m<B and m<C

OpenStudy (nerdy_3000):

well for these m<A,13.6 m<B,72.9 and m<C 1.8

OpenStudy (anonymous):

hold on pls

OpenStudy (anonymous):

isn't m<c 90 degrees??

OpenStudy (nerdy_3000):

Well my teacher told me that we had to find sine^-1 and multiply it by 4/126

OpenStudy (anonymous):

that is when you are finding angles but in this case, if you say m<C is not 90degrees then you don't have a right angled triangle then

OpenStudy (anonymous):

were you trying to type 13.6 instead of 126???

OpenStudy (nerdy_3000):

oh okay because I swear I saw my teacher write down 126 well okay

OpenStudy (nerdy_3000):

because Rose dryer told me to do cos rather than sine??? so I wasn't sure

OpenStudy (anonymous):

she told you the angle was 90degrees at <C??

OpenStudy (anonymous):

^^look up the previous comments

OpenStudy (anonymous):

are you there??

OpenStudy (nerdy_3000):

yeah I know,so the ones you gave me for the lowercase ones are correct?

OpenStudy (anonymous):

yes...i think that should be it

OpenStudy (anonymous):

can you find the angles??

OpenStudy (nerdy_3000):

the angles m<A,13.6 m<B,72.9 and m<C 1.8

OpenStudy (anonymous):

m<C is supposed to be 90degrees because of the right-angle symbol

OpenStudy (nerdy_3000):

Oh okay sorry I forgot to change that

OpenStudy (nerdy_3000):

but the rest are correct right

OpenStudy (anonymous):

if m<c is 90 degrees, and you found m<B to be 72.9 degrees, then m<17.1

OpenStudy (anonymous):

i meant m<C to be 17.1 degrees because you know angles in a triangle add up to 180degrees...so if you have already found twp, you could find the last one....that is how i found m<c to be 17.1degrees

OpenStudy (anonymous):

**if you have already found two

OpenStudy (anonymous):

do you understand me??

OpenStudy (nerdy_3000):

Yes I do

OpenStudy (nerdy_3000):

and for 107 do I do the same for m<C

OpenStudy (nerdy_3000):

and it does not equal to ninety

OpenStudy (anonymous):

for 107, m<C is still 90degrees because of the right-angled symbol at C

OpenStudy (nerdy_3000):

Okay Thanks

OpenStudy (anonymous):

you are welcome...(: Hope you understand everything now

OpenStudy (nerdy_3000):

Yes I do Thank you very much :D

OpenStudy (anonymous):

yw!..(:

OpenStudy (phi):

FYI @RoseDryer for 4.5×cos26=x the 26º was treated as radians, so you got 2.91113695048=x if you use google, type in 4.5 x cos(26 deg)= you get x= 4.04 or about 4.0 In acos(0.29411764705) the answer was returned in radians. If you use google, and you want degrees, type in acos(0.29411764705) in degrees or, if using, calculator, be sure to be in "degree mode"

OpenStudy (anonymous):

My calculator is all messed up right now, it will only do radians. I just need to reset the whole thing.

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