Can someone check these and help me with both? http://oi39.tinypic.com/2qish7r.jpg
So for 107 we have that <A=26 <B=64 <C=90
And BC=2 AC=4.1 AB=4.5
So the 90 is coming from the angle measure of the triangle,right?
Well it says it's a right triangle which means it's 90 degrees.
okay!
Also, For the sides. \[\cos 26 =\frac{ x }{ 4.5 }\] \[4.5\times \cos 26=x\] \[2.91113695048=x\] or \[2.9=x\] AC=2.9
Then for the other side \[\cos64=\frac{ y }{ 4.5 }\] \[4.5\times \cos 64=y\] \[1.76335753693=\] or \[1.8=y\] BC=1.8
For the next one. I know I do this but what do I need to plug in or do I have to plug something in? \[\sin^{-1} \frac{ 4 }{ 126 }\]
^108.
Well first off where did you get 126?
Do this. \[\cos^{-1} (\frac{ 4 }{ 13.6 })\] To find angle B.
Is there a calculator online to do this???
Go to google and search 4/13.6 a calculator will pop up.
Then what should I do with the Cos^-1
Do \[\cos^{-1}(0.29411764705)\] But that comes out as 1.27226412562 which seems a little odd...
@phi @amistre64
@kausarsalley
@RoseDryer I found this calculator and it gave me this answer
what are you trying to find??
108 so far
are you finding the length of AB on question 107??
are you there??
no 108...sorry
so are you finding the length AB??
Well the a and b are separated but yes
what you found for b is right.
okay! then what should I do for the lowercase ones??
don't you think the lower case ones are suppose to be for the lengths and the upper case onea are for angles you are supposed to find??
Yes, so the lowercase ones is 72.9 or is it the m<B
i am saying that isn't is supposed to look like this?: a=4 b=13 c=13.6 and what you are left to find is m<A, m<B and m<C??
just asking you to be sure if it is nit like that, then okay..
Well see this is what I have so far.
the distances you find are for the lower case letters and the angles you find are for the upper case letters
Alright so the ones I have are correct?
if that is the case, then a=4 b=13.0 c=13.6
Thank You Very Much!!!!! :-)
is that it?? are you not supposed to find m<A, m<B and m<C
well for these m<A,13.6 m<B,72.9 and m<C 1.8
hold on pls
isn't m<c 90 degrees??
Well my teacher told me that we had to find sine^-1 and multiply it by 4/126
that is when you are finding angles but in this case, if you say m<C is not 90degrees then you don't have a right angled triangle then
were you trying to type 13.6 instead of 126???
oh okay because I swear I saw my teacher write down 126 well okay
because Rose dryer told me to do cos rather than sine??? so I wasn't sure
she told you the angle was 90degrees at <C??
^^look up the previous comments
are you there??
yeah I know,so the ones you gave me for the lowercase ones are correct?
yes...i think that should be it
can you find the angles??
the angles m<A,13.6 m<B,72.9 and m<C 1.8
m<C is supposed to be 90degrees because of the right-angle symbol
Oh okay sorry I forgot to change that
but the rest are correct right
if m<c is 90 degrees, and you found m<B to be 72.9 degrees, then m<17.1
i meant m<C to be 17.1 degrees because you know angles in a triangle add up to 180degrees...so if you have already found twp, you could find the last one....that is how i found m<c to be 17.1degrees
**if you have already found two
do you understand me??
Yes I do
and for 107 do I do the same for m<C
and it does not equal to ninety
for 107, m<C is still 90degrees because of the right-angled symbol at C
Okay Thanks
you are welcome...(: Hope you understand everything now
Yes I do Thank you very much :D
yw!..(:
FYI @RoseDryer for 4.5×cos26=x the 26º was treated as radians, so you got 2.91113695048=x if you use google, type in 4.5 x cos(26 deg)= you get x= 4.04 or about 4.0 In acos(0.29411764705) the answer was returned in radians. If you use google, and you want degrees, type in acos(0.29411764705) in degrees or, if using, calculator, be sure to be in "degree mode"
My calculator is all messed up right now, it will only do radians. I just need to reset the whole thing.
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