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Pre-Algebra 14 Online
OpenStudy (anonymous):

Help me with three questions??? I don't understand this??

OpenStudy (anonymous):

5. Find the solution to the system of equations by using either graphing or substitution. y = 6 – x and y = x – 2 (1 point) (2, 4) (–4, 2) (4, 2) no solutions 6. y = 2x – 1 and y = x + 3 (1 point) (4, 7) (7, 4) (–7, –4) infinite solutions 7. y = 4x and y + x = 5 (1 point) (–4, 1) (1, 4) (–3, 2) (2, 3)

OpenStudy (anonymous):

I don't understand how to do this

OpenStudy (zzr0ck3r):

tell me if you don't understand anything, else do the same thing on each one.

OpenStudy (anonymous):

Thank you so much!!!

OpenStudy (zzr0ck3r):

y = 6-x y = x-2 this last one implies x = y+2 now plug that into the first one y = 6 - (y+2) y = 6 - y - 2 simplify 2y = 4 y = 2 now plug y into either equation 2 = 6 - x x = 4 so (4,2)

OpenStudy (anonymous):

So for the second one I have to plug in x+3 so it will be y = 2x – 1(x+2)

OpenStudy (anonymous):

I mean y = 2x – 1(x+3)

OpenStudy (anonymous):

how do I simplify it?

OpenStudy (zzr0ck3r):

y = 2x-1 y = x+3 the last one imples x = y - 3 plug that into the first y = 2*(y-3) - 1

OpenStudy (zzr0ck3r):

notice y = 2* something - 1 x is that something we use y = x+3 to write x = y - 3 so our something is y -3 so 2*something - 1 = 2(y-3) - 1

OpenStudy (zzr0ck3r):

now we have y = 2(y-3) - 1

OpenStudy (anonymous):

you explain this so much better than my teacher Thanks!!!

OpenStudy (zzr0ck3r):

np: now solve for 2(y-3) - 1 = y 2y - 6 - 1 = y y = 7 so since y = x+3 7 = x+3 so x = 4 so (4,7)

OpenStudy (anonymous):

so for the third one it is y = 4x(y + x = 5)

OpenStudy (zzr0ck3r):

y = 4x and y + x = 5 pick the second equation and tell me what x =

OpenStudy (zzr0ck3r):

better yet

OpenStudy (zzr0ck3r):

on the second equation we have y + x = 5 according to the 1st equation what is y = ?

OpenStudy (anonymous):

4x

OpenStudy (zzr0ck3r):

so put that where ever you see a y in the second equation and tell me what that looks like

OpenStudy (anonymous):

4x+4=5

OpenStudy (zzr0ck3r):

why 4x + 4?

OpenStudy (anonymous):

argh i mean 4x+x=5

OpenStudy (zzr0ck3r):

right

OpenStudy (zzr0ck3r):

so what is x?

OpenStudy (zzr0ck3r):

what is 4x+1x?

OpenStudy (anonymous):

5

OpenStudy (anonymous):

so x=1

OpenStudy (zzr0ck3r):

let x = apples if you have 4 apples and I give you another apples what do you have?

OpenStudy (anonymous):

5 apples

OpenStudy (zzr0ck3r):

4x+x = 5 5x = 5 x = 1

OpenStudy (zzr0ck3r):

yes

OpenStudy (zzr0ck3r):

you said 5 I think you meant 5x

OpenStudy (anonymous):

yes!!

OpenStudy (zzr0ck3r):

ok so if x = 1, what is y?

OpenStudy (zzr0ck3r):

pick either equation

OpenStudy (anonymous):

i mean 4x

OpenStudy (zzr0ck3r):

so what is y if x is 1?

OpenStudy (anonymous):

so I'm using the second equation 1+3=4?

OpenStudy (anonymous):

does that mean the answer is B (1, 4)?

OpenStudy (zzr0ck3r):

you can use either equation they will tell you the same thing equation 1 y = 4x x = 1 so y = 4*x --> y = 4*1 --> y = 4

OpenStudy (zzr0ck3r):

second equation y + x = 5 x = 1 so y + 1 = 5 so y = 4

OpenStudy (zzr0ck3r):

after you solve for one of the variables using substitution you plug that value into either of your starting equations and solve for the other variable.

OpenStudy (anonymous):

Thank you so much I wish you were my teacher instead of the one I have right now!!

OpenStudy (zzr0ck3r):

example 4+x = y 3y = 6 now since y = 4 + x 3y=6 --> 3*(4+x) = 6 we solve for x 12+3x = 6 3x = -6 x = -2 now we know what x is so now pick the easier equation to figure out what y is y = 4+x and we know x = -2 so y = 4-2 y =2 so (-2,2)

OpenStudy (anonymous):

Thank you I get it now!!! Thanks for you time and for teaching me this.

OpenStudy (zzr0ck3r):

this was a silly example and could be done a much easier way but I wanted to give you a basic case.

OpenStudy (zzr0ck3r):

ok good luck

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