Help me with three questions??? I don't understand this??
5. Find the solution to the system of equations by using either graphing or substitution. y = 6 – x and y = x – 2 (1 point) (2, 4) (–4, 2) (4, 2) no solutions 6. y = 2x – 1 and y = x + 3 (1 point) (4, 7) (7, 4) (–7, –4) infinite solutions 7. y = 4x and y + x = 5 (1 point) (–4, 1) (1, 4) (–3, 2) (2, 3)
I don't understand how to do this
tell me if you don't understand anything, else do the same thing on each one.
Thank you so much!!!
y = 6-x y = x-2 this last one implies x = y+2 now plug that into the first one y = 6 - (y+2) y = 6 - y - 2 simplify 2y = 4 y = 2 now plug y into either equation 2 = 6 - x x = 4 so (4,2)
So for the second one I have to plug in x+3 so it will be y = 2x – 1(x+2)
I mean y = 2x – 1(x+3)
how do I simplify it?
y = 2x-1 y = x+3 the last one imples x = y - 3 plug that into the first y = 2*(y-3) - 1
notice y = 2* something - 1 x is that something we use y = x+3 to write x = y - 3 so our something is y -3 so 2*something - 1 = 2(y-3) - 1
now we have y = 2(y-3) - 1
you explain this so much better than my teacher Thanks!!!
np: now solve for 2(y-3) - 1 = y 2y - 6 - 1 = y y = 7 so since y = x+3 7 = x+3 so x = 4 so (4,7)
so for the third one it is y = 4x(y + x = 5)
y = 4x and y + x = 5 pick the second equation and tell me what x =
better yet
on the second equation we have y + x = 5 according to the 1st equation what is y = ?
4x
so put that where ever you see a y in the second equation and tell me what that looks like
4x+4=5
why 4x + 4?
argh i mean 4x+x=5
right
so what is x?
what is 4x+1x?
5
so x=1
let x = apples if you have 4 apples and I give you another apples what do you have?
5 apples
4x+x = 5 5x = 5 x = 1
yes
you said 5 I think you meant 5x
yes!!
ok so if x = 1, what is y?
pick either equation
i mean 4x
so what is y if x is 1?
so I'm using the second equation 1+3=4?
does that mean the answer is B (1, 4)?
you can use either equation they will tell you the same thing equation 1 y = 4x x = 1 so y = 4*x --> y = 4*1 --> y = 4
second equation y + x = 5 x = 1 so y + 1 = 5 so y = 4
after you solve for one of the variables using substitution you plug that value into either of your starting equations and solve for the other variable.
Thank you so much I wish you were my teacher instead of the one I have right now!!
example 4+x = y 3y = 6 now since y = 4 + x 3y=6 --> 3*(4+x) = 6 we solve for x 12+3x = 6 3x = -6 x = -2 now we know what x is so now pick the easier equation to figure out what y is y = 4+x and we know x = -2 so y = 4-2 y =2 so (-2,2)
Thank you I get it now!!! Thanks for you time and for teaching me this.
this was a silly example and could be done a much easier way but I wanted to give you a basic case.
ok good luck
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