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If I=indefinite integral of (sqrt(a^2x^2-b^2)/x) dx and x=c*sec(u) so that the substitution reduces I to b*integral of (tan(u))^2*du. Hence evaluate I.
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HELP?
Does anyone have a clue?
\[\large \int\limits \frac{\sqrt{a^2x^2-b^2}}{x}dx\]It's a little bit hard to read in text, does this look correct?
If you're using Internet Explorer, you'll have trouble viewing the code. Lemme know if it's just a bunch of ugly jumbled up text.
yes thats correct
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They're just telling you to make a `Trig Substitution` in order to solve this integral. Have you had much work with trig subs yet? This one is a tiny bit tricky.
we just started trig subs. Im fine with it but I am not successful with this one at all
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