2x+9y=0 3x+5y=17
@merchandize
Solve by yourself. It is same as previous one.
im not in algebraanymore, its just a review i dont remember how, it confuses me
I know what it is. Give a try wherever you find problem then ask me. Not like that..sorry..:(
which equation do i use first? to plug into the other one
any one of them either equation 1 or 2. okay i will give you a hint from equation 2 5y=17-3x. now i am not going to give you any hint.. solve by yourself.
ok
so i plug that in where the x is in the first equation?
i plg in 17-3x
so it will be 2(17-3x) +97= 0 rite ?
hello?
2x + 9y = 0 3x + 5y = 17 multiply the first equation by 3 and the second by 2; then subtract 6x + 27y = 0 6x + 10y = 34 17y = -34 y = -2 substitute to find 'x' 2x + 9(-2) = 0 2x -18 = 0 2x = 18 x = 9 check by substituting these values into the other equation 3(9) + 5(-2) = 17 ?? 27 -10 = 17 Answer: (9,-2) Do you wanna know how to graph it?
no i don't need to graph, thnx!
lol noproblem :D
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