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OpenStudy (anonymous):
@merchandize
OpenStudy (merchandize):
Solve by yourself. It is same as previous one.
OpenStudy (anonymous):
im not in algebraanymore, its just a review i dont remember how, it confuses me
OpenStudy (merchandize):
I know what it is. Give a try wherever you find problem then ask me. Not like that..sorry..:(
OpenStudy (anonymous):
which equation do i use first? to plug into the other one
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OpenStudy (merchandize):
any one of them
either equation 1 or 2.
okay i will give you a hint
from equation 2
5y=17-3x.
now i am not going to give you any hint..
solve by yourself.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so i plug that in where the x is in the first equation?
OpenStudy (anonymous):
i plg in 17-3x
OpenStudy (anonymous):
so it will be 2(17-3x) +97= 0 rite ?
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OpenStudy (anonymous):
hello?
OpenStudy (anonymous):
2x + 9y = 0
3x + 5y = 17
multiply the first equation by 3 and the second by 2; then subtract
6x + 27y = 0
6x + 10y = 34
17y = -34
y = -2
substitute to find 'x'
2x + 9(-2) = 0
2x -18 = 0
2x = 18
x = 9
check by substituting these values into the other equation
3(9) + 5(-2) = 17 ??
27 -10 = 17
Answer: (9,-2)
Do you wanna know how to graph it?