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Use the product rule to simplify
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\[-\sqrt[3]{81x^{10}y^5}\]
It has been a long time...
- 3 cube root 3 x X^10/3 x Y^ 5/3
So, I know my first thing to do is see if I can make it a perfect cube. And I know 27, which has a perfect cube, *3 is 81. \[=-\sqrt[3]{27x^{9}y ^{3}*(3xy ^{2)}}\]
Then what? Simplify the first part to =3x^3y?
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And don't the rest of it stay the same?
give me the original question and ill attach the method
Thanks
Ignore the "y" at the edge of the page.
Well you can use this \[\left( a ^{b} \right)^{c} = a ^{b \times c}\]
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In this case c would be 1/3 which represents the root
I think I got it now, thanks.
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