write an equation of the line containing the specified point and parallel to the indicated line. (-3,6),y=7
chris
?
Eyeball problem. y = 7 is an horizontal line, therefore, the horizontal line passing through (-3,6) is y = 6
can you please explain it how you got it.
Just did. The full explanation is included already. What is the y-coordinate of (-3,6)?
7
?? How about 6?
this is so confusing
Here is an horizontal line. y = 7 This lines contains all points with a y-coordinate of 7. (0,7), (-4,7), (36,7), (523,7) Here is a point (-3,6) This clearly is not on the line y = 7, since it's y-coordinate is 6. This causes us to wonder, what is the equation of the horizontal line that contains this point? Here is a horizontal line y = 6 This lines contains all points with a y-coordinate of 6. (0,6), (-4,6), (36,6), (523,6) and even (-3,6)
so as my equation i can put (-3,6)y=6
y = 6 is parallel to y = 7. This meets one of the criteria of the problem statement. y = 6 contains the point (-3,6). This meets the second criterion of the problem statement. That is all that is required and we are done. Just for fun, can you name the VERTICAL line that passes through (-3,6)?
(-3,9)
hi chris
Join our real-time social learning platform and learn together with your friends!