if an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h=-16t^2+vt+s, where h is in feet. if the object is propelled from a height of 8 feet with an initial velocity of 96 feet per second, its height h given by the equation h=-16t^2+96t+8. after how many seconds is the height 116 feet?

Question

anonymous · Answer

h=-16t^2+vt+s
                  ^ initial velocity
                       ^ initial height. 

just plug in I suppose

anonymous · Answer

h=116
v=96
s=8

so plug in all of it and solve for t using your favorite method for solving quadratics.