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Evaluate log2 5 to the nearest thousandth. 2 is the base.
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\(\huge log_25?\)
... 2 is the base... darn, I just read hehe, so I guess I got my answer, anyhow, since calculators don't have \(\large log_2\) or else, just \(\large log_10\) , then use the "log change of base rule" http://www.teachengineering.org/collection/van_/lessons/van_bmd_less3/change_of_base_lesson3_image1.jpg
\(log_{10}\) I meant there :)
Thanks.
yw
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