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Calculus1
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integrals with trig function in denominator
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\[\frac{ dx }{5+4cosx ? }\]
i know you have to let tan =x/2 then sinx = 2t/1+t^2 and cos x = 1-t^2/1+t^2
yes ... you are in right direction
i've solved and ended with \[2\int\limits_{}^{}\frac{ 1+t^2 }{ 5+\frac{ 4-4t^2 }{1+t^2 } }\]
simplify it
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if i divide by 1+t^2 then what will happen to the 5?
http://en.wikipedia.org/wiki/Weierstrass_substitution \[ \int \frac{1}{5 + 4 \cos x} dx = \int \frac{1}{5 + 4 \frac{1-t^2}{1+t^2}} \cdot \frac{2 dt}{1+t^2} = 2 \int \frac{1}{9 + t^2}dt\] i suppose you can solve after it.
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