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SQUARE ROOT OF 4N^3
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\[\sqrt{4n^3}=2n \sqrt{n}\]
HOW U GET THAT
well the square root of 4 is 2 so you can bring that out and since there are 3 n's, you can bring one of them out
smarty:)
How come u can just get 1 of the n's out?
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#confused
it's like \[\sqrt{4}=\sqrt{2*2}\] \[\sqrt{n^3}=\sqrt{(n*n)*n}\]
ohh ok since the s ns are sort of like perfect swuares cuz 2 is a perfect sqaure the 3 is taken out?
I have a hard time reading that ^_^'
\[\large \sqrt{4n^3}= \sqrt{\color{red}{2*2}*\color{blue}{n*n}*n} \implies 2n \sqrt{n}\]
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pretty much what the smartypants above me showed :P
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