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Mathematics 13 Online
OpenStudy (anonymous):

Find the product. (y2)5 · y8

OpenStudy (anonymous):

sorry those are exponents

OpenStudy (anonymous):

Like this? \[(y^2)^5 · y^8\]

OpenStudy (anonymous):

yes like that

OpenStudy (anonymous):

okay for y^2)^5 use this rule \[X^m)^n = x^{m*n}\]

OpenStudy (anonymous):

do you know this rule?

OpenStudy (anonymous):

yes i know this rule somewhat lol im bad at math so

OpenStudy (anonymous):

well y^2)^5 uses this rule, so multiply 5 by 2 you get y^10

OpenStudy (anonymous):

now you have \[y^{10} * y^8\] and use this rule----> \[y^m * y^n = y^{m+n}\]

OpenStudy (anonymous):

and voila the answer

OpenStudy (anonymous):

so the answer is 7a^4b^3

OpenStudy (anonymous):

...what?

OpenStudy (anonymous):

where did you get a and b from? the wuestion only has y.

OpenStudy (anonymous):

sorry i was looking at a different question

OpenStudy (anonymous):

..lol i was like totally flabbergasted, i was like what just happened? anyway do you know the answer?

OpenStudy (anonymous):

a. y^23 b. y^18 c. (y)^40 d. y^5

OpenStudy (anonymous):

those are the choices

OpenStudy (anonymous):

i think it is b

OpenStudy (anonymous):

yyup ur correct

OpenStudy (anonymous):

now can u help with another problem

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

Find the product. (-3ab2)3

OpenStudy (anonymous):

what is it?

OpenStudy (anonymous):

Find the product. (-3ab^2)^3 my choices are a.) 27ab b.) -23a^2b^2 c.) -9a^3b^5 d.) -27a^3b^6

OpenStudy (anonymous):

simple everything inside the brackets are going to be affected nby the exponent first step: what is -3^3?

OpenStudy (anonymous):

-27

OpenStudy (anonymous):

good then what is a^3... well that's actually just a^3

OpenStudy (anonymous):

finally what b^2)^3

OpenStudy (anonymous):

b^6

OpenStudy (anonymous):

now put it together

OpenStudy (anonymous):

-27a^3b^6

OpenStudy (anonymous):

yup :)

OpenStudy (anonymous):

willing to help me with a few more??????

OpenStudy (anonymous):

if not thats ok but just asking

OpenStudy (anonymous):

no problem

OpenStudy (anonymous):

what else do you need help with?

OpenStudy (anonymous):

Find the product (a2b3)4

OpenStudy (anonymous):

(a^2b^3)^4

OpenStudy (anonymous):

same thing as before whats a^2)^4

OpenStudy (anonymous):

a^8 ?

OpenStudy (anonymous):

yup and b^3)^4?

OpenStudy (anonymous):

b^12

OpenStudy (anonymous):

yup and put it together

OpenStudy (anonymous):

yay i was right XD lol i had that the first time i just wasnt sure

OpenStudy (anonymous):

exactly its not so bad after a couple of problems

OpenStudy (anonymous):

one more

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

hit me

OpenStudy (anonymous):

(n^3)^2 · (n^5)^4 i got n^26

OpenStudy (anonymous):

that's right! :)

OpenStudy (anonymous):

XD yay really

OpenStudy (anonymous):

:D im glad you got the hang of it, anymore you want to try?

OpenStudy (anonymous):

nope. im finished, thank you for all your help :D

OpenStudy (anonymous):

no problem bye!

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