Mathematics
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OpenStudy (anonymous):
Find the product.
(y2)5 · y8
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OpenStudy (anonymous):
sorry those are exponents
OpenStudy (anonymous):
Like this?
\[(y^2)^5 · y^8\]
OpenStudy (anonymous):
yes like that
OpenStudy (anonymous):
okay for y^2)^5 use this rule \[X^m)^n = x^{m*n}\]
OpenStudy (anonymous):
do you know this rule?
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OpenStudy (anonymous):
yes i know this rule somewhat lol im bad at math so
OpenStudy (anonymous):
well y^2)^5 uses this rule, so multiply 5 by 2
you get y^10
OpenStudy (anonymous):
now you have \[y^{10} * y^8\] and use this rule----> \[y^m * y^n = y^{m+n}\]
OpenStudy (anonymous):
and voila the answer
OpenStudy (anonymous):
so the answer is 7a^4b^3
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OpenStudy (anonymous):
...what?
OpenStudy (anonymous):
where did you get a and b from?
the wuestion only has y.
OpenStudy (anonymous):
sorry i was looking at a different question
OpenStudy (anonymous):
..lol i was like totally flabbergasted, i was like what just happened? anyway do you know the answer?
OpenStudy (anonymous):
a. y^23
b. y^18
c. (y)^40
d. y^5
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OpenStudy (anonymous):
those are the choices
OpenStudy (anonymous):
i think it is b
OpenStudy (anonymous):
yyup ur correct
OpenStudy (anonymous):
now can u help with another problem
OpenStudy (anonymous):
sure
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OpenStudy (anonymous):
Find the product.
(-3ab2)3
OpenStudy (anonymous):
what is it?
OpenStudy (anonymous):
Find the product. (-3ab^2)^3
my choices are
a.) 27ab
b.) -23a^2b^2
c.) -9a^3b^5
d.) -27a^3b^6
OpenStudy (anonymous):
simple everything inside the brackets are going to be affected nby the exponent first step: what is -3^3?
OpenStudy (anonymous):
-27
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OpenStudy (anonymous):
good then what is a^3...
well that's actually just a^3
OpenStudy (anonymous):
finally what b^2)^3
OpenStudy (anonymous):
b^6
OpenStudy (anonymous):
now put it together
OpenStudy (anonymous):
-27a^3b^6
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OpenStudy (anonymous):
yup :)
OpenStudy (anonymous):
willing to help me with a few more??????
OpenStudy (anonymous):
if not thats ok but just asking
OpenStudy (anonymous):
no problem
OpenStudy (anonymous):
what else do you need help with?
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OpenStudy (anonymous):
Find the product
(a2b3)4
OpenStudy (anonymous):
(a^2b^3)^4
OpenStudy (anonymous):
same thing as before whats a^2)^4
OpenStudy (anonymous):
a^8 ?
OpenStudy (anonymous):
yup and b^3)^4?
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OpenStudy (anonymous):
b^12
OpenStudy (anonymous):
yup and put it together
OpenStudy (anonymous):
yay i was right XD lol i had that the first time i just wasnt sure
OpenStudy (anonymous):
exactly its not so bad after a couple of problems
OpenStudy (anonymous):
one more
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OpenStudy (anonymous):
okay
OpenStudy (anonymous):
hit me
OpenStudy (anonymous):
(n^3)^2 · (n^5)^4
i got n^26
OpenStudy (anonymous):
that's right! :)
OpenStudy (anonymous):
XD yay really
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OpenStudy (anonymous):
:D im glad you got the hang of it, anymore you want to try?
OpenStudy (anonymous):
nope. im finished, thank you for all your help :D
OpenStudy (anonymous):
no problem bye!