Solve the equation \[\sqrt{2x-3}\] +5 =6
draw it.
\[\sqrt{2x-3}\] +5 =6 like this
you can subtract 5 fom both sides, first
There's no need to draw it though
but its not underneath its next to it
then squaring both sides will make it much simpler then
im so confused
isolate the square root sign by subtracting 5 from both sides...can u?
yea i did that and got 1
correct...now square both sides..
ok and i got 4x²-20x+25
actually, squaring and square root gets cancelled \((\sqrt{A})^2=A\) so, \((\sqrt{2x-3})^2=2x-3\) only got this ?
I will show you how it's done just now that is if you will like how I will do it but even if you don't like my way I will do it my way anyway : \[\sqrt{2x-3}+5=6 \rightarrow \sqrt{2x-3}=6-5 \rightarrow \sqrt{2x-3}=1 \] And now you can square both sides of the equation as follows \[\left( \sqrt{2x-3} \right)^2 = 1^2 \] \[2x-3=1\] \[2x=4 \rightarrow x=2\] but you need to go back and check if the solution makes sense or not hey by substituting your result into the original equation \[\sqrt{2(2)-3} +5=6\] \[\sqrt{4-3}+5=6 \rightarrow \sqrt{1}+5=6 \rightarrow 1+5=6 \] and you can see that hey the left hand side is equal to the right hand side which means that the solution makes sense \[6=6 \rightarrow RHS=LHS\] as expected
kinda?
so its just 2x-3 =1 aon't this easy to solve ?
*ain't
yea i its x=2
correct :)
Does the answer make sense to you though ? Indiandabest ???
i mean kinda i kinda know what to do from now on
Dont I deserve a medal for this at least :)
lol yea
Hahaha thanks
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