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Mathematics 15 Online
OpenStudy (anonymous):

Someone please help explain this to me? I'm desperate!

OpenStudy (anonymous):

27. Suppose y varies inversely with x. Write an equation for the inverse variation. Y = 7 when x = 3 28. Suppose y varies inversely with x. Write an equation for the inverse variation. Y = 4 when x = 2.5 29. Suppose y varies inversely with x. Write an equation for the inverse variation. Y = -9 when x = 2 30. Suppose y varies inversely with x. Write an equation for the inverse variation. Y = 5 when x = -5 31. Graph each inverse variation. Xy = 15 32. Graph each inverse variation. Y = -18 / x 34. Identify the excluded value for each function. F(x) = 5 / x 35. Identify the excluded value for each function. Y = 3 / x + 4 36. Identify the asymptotes of the graph of each function. Then graph the function. Y = 1 / x + 2 37. Identify the asymptotes of the graph of each function. Then graph the function. F(x) = -2 / x + 3 38. Identify the asymptotes of the graph of each function. Then graph the function. Y = 5 / x – 4 + 1 39. Identify the asymptotes of the graph of each function. Then graph the function. F(x) = 3 / x – 5 – 1 I know it's a lot, but please! Someone help me with this and explain it to me so I can do it on my own! I really am desperate to know how to do this

OpenStudy (anonymous):

Or at least help me with one

OpenStudy (anonymous):

I know it's more than I should have posted but really I need help and I know the people here can teach me

OpenStudy (anonymous):

Please

OpenStudy (anonymous):

@amistre64 you've helped me in the past! (: Can you help me now?

OpenStudy (luigi0210):

Well let's do one, any number you have in mind?

OpenStudy (anonymous):

27

OpenStudy (luigi0210):

Do you know how to start?

OpenStudy (amistre64):

the inverse of a number a, is 1/a an inverse variation is one of the form y= k/x

OpenStudy (amistre64):

inverse variation has a constant k of: xy a direct variation has a constant k of: y/x so essentially they want you to express this with the given values: y = (XY)/x for an inverse y = (Y/X) x for a direct

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