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why do you get extraneous equations when solving rational equations
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Explain why it is important to check your answers when solving equations with rational expressions. ^original question
go for it @dumbcow xD
because you can't divide by zero is 1 reason example: haha having trouble coming up with rational equation with extraneous solution
Gave you one xD
thx \[\frac{1}{x-1}= \frac{3}{x+2}-\frac{6x}{(x-2)(x+2)}\] this yields 2 solutions: x=-2 and x=5/4 -2 is extraneous, because when you plug it in it makes the denominator 0 which is undefined
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you know right away that x=1, x=2, x=-2 are all extraneous solutions because they cause function to be undefined
thank you!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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