Question

ho do i fix 3 over sqrt(2)

Answer 1

is it broken ? :)

Answer 2

Haha

Answer 3

@Gabylovesyou Madam please elaborate your question

Answer 4

http://www.wolframalpha.com/input/?i=3+over+sqrt%282%29

Answer 5

To "fix" it, multiply by \[\frac{\sqrt{2}}{\sqrt{2}}\]and simplify.

Answer 6

To "fix" more complicated expressions, such as
\[\frac{1}{a-b}\]try multiplying by the conjugate of the denominator:
\[\frac{1}{a-b}*\frac{a+b}{a+b} = \frac{a+b}{(a+b)(a-b)} = \frac{a+b}{a^2-b^2}\]
Notice that if \(a\) or \(b\) had contained a square root, we would have eliminated the radical sign from the denominator by doing this.