39. Write the equation of a line that is perpendicular to the given line and that passes through the given point.
y + 2 = 1/3 (x – 5); (–4, 3) (1 point)

y = –3x + 15
y = –3x – 9
y = –4x + 3
y = –1/3 x – 11

Question

39.   Write the equation of a line that is perpendicular to the given line and that passes through the given point. 
y + 2 = 1/3 (x – 5); (–4, 3)  (1 point)

y = –3x + 15
y = –3x – 9
y = –4x + 3
y = –1/3 x – 11

anonymous · Answer

It's the second one because you take the negative reciprocal of the given slope to get a new slope:

-3

Now, you use the point-slope formula:

y - y1 = m(x - x1)

y - 3 = (-3)[x - (-4)]

y = –3x – 9

anonymous · Answer

Just... Thank you, I truly do appreciate it.

anonymous · Answer

You're always very welcome and it's a great privilege working with such a nice person as yourself! @sgstiles