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compute the discriminant of 2x^2-4x+9=2
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If I'm right the discriminant is: \[\sqrt{b^2-4(ac)}\]
oh yeah that's it
do you know then how to describe the solutions
So just plug in values:\[\sqrt{(-4)^2-4(2)(7)}\]
and you have to set the original equal to 0: \[2x^2-4x+7=0\]
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how do I use \[\sqrt{-40}\] to describe a solutions
when it's negative that means that there are no REAL solutions.. there are gonna be imaginary solutions
ok thanksss
Np :P
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