Which of the following groups of side lengths would form a right triangle? A. 4 cm, 5 cm, 6 cm B. 7 cm, 24 cm, 25 cm C. 8 cm, 16 cm, 30 cm D. 10 cm, 40 cm, 50 cm
hey
so you have to use the pythgorean theorem which is a^2+b^2=c^2
yes
ok so its just a guess and check and c must always be the biggest side
so it c
also the 7 24 25 is a special right triangle so you know that will always work along with the 3 4 5 triangle and others
so for e first one it would be 4^2+5^2=6^2 which is 16+25=36 ------> 41 doesn't equal 36 therefore its not that one
A right triangle has sides measuring 6 units, 8 units, and 10 units. Which of the following shows the Pythagorean relationship of the areas of the squares drawn along each side? A. 12 + 16 = 28 B. 18 + 24 = 42 C. 24 + 76 = 100 D. 36 + 64 = 100
no its not c because 8^2+16^2 doesn't equal 30^2
the answer for the previous one is b
the new ques is 6^2+8^2=10^2 so you just have to compute that and you will find the answer
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