Identify the center of the circle whose equation is
(x - 2)² + (y + 8)² = 16.

Question

Identify the center of the circle whose equation is
(x - 2)² + (y + 8)² = 16.

anonymous · Answer

PLEASE HELP HAVE TO HAVE THIS TEST TURNED IN BY 12AM

mertsj · Answer

Do I understand that you are cheating on a test?

anonymous · Answer

No i didnt ask for the answer i need help learning how to solve it like an example

mertsj · Answer

$$(x-h)^2+(y-k)^2 = r^2 $$

mertsj · Answer

Equation of a circle.  Center (h,k) radius = r

anonymous · Answer

ok so do i use the that equation

anonymous · Answer

i need some help totaly confused

whpalmer4 · Answer

@Mertsj has given you the formula and description.  Now you have to match up your equation with the formula, and interpret it.

whpalmer4 · Answer

Look at the first term: $(x-2)^2$
Compare with the formula: $(x-h)^2$ where $h$ is the $x$-coordinate of the center of the circle.  Any ideas?

whpalmer4 · Answer

Do the same with $y$ and $r$ terms.  Note that the $y$ term has a + in it instead of a - sign.  How do you subtract, yet end up adding?

anonymous · Answer

This original equation is (x-#) +(y-#)=radius
The center is (2, -8) because when you plug in -8, negative plus a negative equals a positive. 2stays the same because you just plug in the number#

anonymous · Answer

Ohhhhhhhhhhh ok

anonymous · Answer

thank yall so much for explaing it