Prove: sec x(1 + cos x) = 1 + sec x
see secx*cosx=1
distribute!
\[\sec(x) = \dfrac{1}{\cos(x)}\]So\[\dfrac{1}{\cos(x)}\left(1 + \cos(x)\right) = 1 + \dfrac{1}{\cos(x)}\]Distribute\[\dfrac{1}{\cos(x)} + 1 = 1 + \dfrac{1}{\cos(x)}\]Don't need to go further
The left hand side is just the right hand side, right?
Presumably
So we're done.
Could be shorter by memorizing \(\sec(x) \times \cos(x) = 1\), but bleh :p
wouldn't you prove it like: secx+secx*cosx =secx+1/cosx*cosx =secx+1
Yeah, that's the shorter way to prove it.
:D
can you elaborate @isuckatmath9999 ? :)i mean elaborate your way. haha
lol there are about 5000* ways, anyone else got another?
@Jhannybean \(\sec(x) \times \cos(x) = 1\)
I don't neeed another its for an assignment lol. :)
yeahhh but how'd he get...sec (x) + 1/cos^2 (x)...
OH YOU FACTORED OUT THE SEC (X)???
yea lol
It's not 1/cos^2(x) lol It's 1/cos(x) * cos(x)
oh ho ho, i gotchu.
I have more questions to debate upon lol. don't worry :P heheee
I haven't done trig in months. Wow
there isn't one
i feel so dyslexic...
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