Mathematics
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OpenStudy (gabylovesyou):
Ho do i do this problem ? lolhttp://www.wolframalpha.com/input/?i=7h%5E2+sqrt%283h%29 @hartnn
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OpenStudy (gabylovesyou):
@ganeshie8
OpenStudy (gabylovesyou):
which part would i check ?
hartnn (hartnn):
yeah, you had to click on
Use h as variable...
hartnn (hartnn):
bdw, what you got ?
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OpenStudy (gabylovesyou):
it doesnt show the answer .-.
ganeshie8 (ganeshie8):
what you wanto do.. simplify or send everything inside radical ? wats the q...
OpenStudy (gabylovesyou):
im supposed to find the equation that simplifies to that
ganeshie8 (ganeshie8):
looks, you just need to send outside stuff to inside
OpenStudy (gabylovesyou):
by multiplying ?
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ganeshie8 (ganeshie8):
\(7h^2\sqrt{3h} \)
ganeshie8 (ganeshie8):
7 = \(\sqrt{7} \times \sqrt{7}\) = \(\sqrt{49}\)
ganeshie8 (ganeshie8):
7 becomes 49, when u take it inside radical
OpenStudy (gabylovesyou):
ok and what do i do with the h
OpenStudy (gabylovesyou):
it becomes h^3 ?
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ganeshie8 (ganeshie8):
\(7h^2\sqrt{3h} \)
\(h^2\sqrt{49 \times 3h} \)
ganeshie8 (ganeshie8):
nopes,
h^2 = \(\sqrt{h^2} \times \sqrt{h^2} = \sqrt{h^?} \)
OpenStudy (gabylovesyou):
h^2?
ganeshie8 (ganeshie8):
h^2 = \(\sqrt{h^2} \times \sqrt{h^2} = \sqrt{h^\color{red}{4}}\)
OpenStudy (gabylovesyou):
oh i thought it stays the same but ok
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ganeshie8 (ganeshie8):
if u take h^4 out of radical , it becomes h^2 again.
write the final expression
ganeshie8 (ganeshie8):
\(7h^2\sqrt{3h} \)
\(h^2\sqrt{49 \times 3h} \)
\(\sqrt{h^4 \times 49 \times 3h} \)
ganeshie8 (ganeshie8):
you can simplify a bit. i think they wanted this when they asked to "find the equation that simplifies to that "
OpenStudy (gabylovesyou):
these r my choices :
sqrt(14h^3)
sqrt(49h^3)
sqrt(147h^5)
sqrt(21h^5)
ganeshie8 (ganeshie8):
great ! simplify the thing above and see what u get :)
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OpenStudy (gabylovesyou):
7 sqrt(3) sqrt(h^5)
OpenStudy (gabylovesyou):
wait no sqrt(147h^5)
ganeshie8 (ganeshie8):
brilliant !
OpenStudy (gabylovesyou):
thank you do much! :)
ganeshie8 (ganeshie8):
np :)