Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (gabylovesyou):

Ho do i do this problem ? lolhttp://www.wolframalpha.com/input/?i=7h%5E2+sqrt%283h%29 @hartnn

OpenStudy (gabylovesyou):

@ganeshie8

OpenStudy (gabylovesyou):

which part would i check ?

hartnn (hartnn):

yeah, you had to click on Use h as variable...

hartnn (hartnn):

bdw, what you got ?

OpenStudy (gabylovesyou):

it doesnt show the answer .-.

ganeshie8 (ganeshie8):

what you wanto do.. simplify or send everything inside radical ? wats the q...

OpenStudy (gabylovesyou):

im supposed to find the equation that simplifies to that

ganeshie8 (ganeshie8):

looks, you just need to send outside stuff to inside

OpenStudy (gabylovesyou):

by multiplying ?

ganeshie8 (ganeshie8):

\(7h^2\sqrt{3h} \)

ganeshie8 (ganeshie8):

7 = \(\sqrt{7} \times \sqrt{7}\) = \(\sqrt{49}\)

ganeshie8 (ganeshie8):

7 becomes 49, when u take it inside radical

OpenStudy (gabylovesyou):

ok and what do i do with the h

OpenStudy (gabylovesyou):

it becomes h^3 ?

ganeshie8 (ganeshie8):

\(7h^2\sqrt{3h} \) \(h^2\sqrt{49 \times 3h} \)

ganeshie8 (ganeshie8):

nopes, h^2 = \(\sqrt{h^2} \times \sqrt{h^2} = \sqrt{h^?} \)

OpenStudy (gabylovesyou):

h^2?

ganeshie8 (ganeshie8):

h^2 = \(\sqrt{h^2} \times \sqrt{h^2} = \sqrt{h^\color{red}{4}}\)

OpenStudy (gabylovesyou):

oh i thought it stays the same but ok

ganeshie8 (ganeshie8):

if u take h^4 out of radical , it becomes h^2 again. write the final expression

ganeshie8 (ganeshie8):

\(7h^2\sqrt{3h} \) \(h^2\sqrt{49 \times 3h} \) \(\sqrt{h^4 \times 49 \times 3h} \)

ganeshie8 (ganeshie8):

you can simplify a bit. i think they wanted this when they asked to "find the equation that simplifies to that "

OpenStudy (gabylovesyou):

these r my choices : sqrt(14h^3) sqrt(49h^3) sqrt(147h^5) sqrt(21h^5)

ganeshie8 (ganeshie8):

great ! simplify the thing above and see what u get :)

OpenStudy (gabylovesyou):

7 sqrt(3) sqrt(h^5)

OpenStudy (gabylovesyou):

wait no sqrt(147h^5)

ganeshie8 (ganeshie8):

brilliant !

OpenStudy (gabylovesyou):

thank you do much! :)

ganeshie8 (ganeshie8):

np :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!