Question

Solve each equation by factoring:

n^2 + 3n - 12 = 6

Answer 1

n^2 + 3n - 12 = 6
n^2 + 3n-18 =0
at this point you can use the quadratic eq or recognizie
(n+6)(n-3)

Answer 2

The way you recognize
(n+a)(n+b) = n^2 + (a+b)n +ab

Answer 3

i get the first part, but now im lost.. sorry!

Answer 4

(n+a)(n+b) = n^2 + (a+b)n +ab
use distributive law and multiple out

Answer 5

n^2 + 3n-18 =0

basically focus on left side

what numbers multiply to get 18 but sum up to 3. and that is 6 and -3

Answer 6

okay! thanks @timo86m that helped alot:P
so the answers are (6,-3) ?

Answer 7

thanx! :)

Answer 8

(n+6)(n-3)= n^2 + 3n-18 = 0

since
(n+6)(n-3)=0 is easier to solve than n^2 + 3n-18 = 0
Just solve
(n+6)(n-3)=0

n=-6 and n=3

Answer 9

Thank you so much! too the both of you! you guys are such a big help! much appreciated! <3 :)

Answer 10

(n+a)(n+b) = n^2 + (a+b)n +ab
use distributive law and multiple out
Therefore and Quadric eq of the form
n^2 + Bn + C
B = a+b
C=ab

Answer 11

thanx! GBU!